You mentioned that in UTF-8, 'Í' is represented by two bytes: 0xC3 and 0x8D. However, in ISO-8859-1 (Latin-1), 'Í' is represented by a single byte: 0xCD. To adjust your code for a UTF-8 encoded environment, you need to handle the two-byte sequence representing 'Í'.
Updated Code for UTF-8:
#include <stdio.h>
#include <string.h>
int main() {
char tmp1[] = "Íexample"; // Example string with 'Í'
char tmp2[] = "another example";
int len = strlen(tmp1);
if (len > 8 && !(tmp1[0] == '\xC3' && tmp1[1] == '\x8D')) {
fprintf(stdout, "\t%s\t%s\n", tmp1, tmp2);
} else if (!(tmp1[0] == '\xC3' && tmp1[1] == '\x8D')) {
fprintf(stdout, "\t%s\t\t%s\n", tmp1, tmp2);
}
return 0;
}
Explanation:
Two-Byte Check:
In UTF-8, the character 'Í' is represented by two bytes: 0xC3 and 0x8D. Therefore, you need to check both consecutive bytes in tmp1.
Condition Update:
We replace the check tmp1[0] != '\xCD' with a double-check: (tmp1[0] == '\xC3' && tmp1[1] == '\x8D') to ensure we are correctly comparing the character 'Í' in UTF-8.
Code Update:
We adjust the if and else if conditions to check for the byte sequence representing 'Í' in UTF-8.
Summary:
Consistent Encoding: Ensure that your source code files are saved with UTF-8 encoding.
Check Both Bytes: When dealing with UTF-8 encoded characters that use multiple bytes, always check the entire byte sequence.
By following these steps, your code should work correctly in a UTF-8 encoded environment.